4WRE6W1-16-1X/24K4/M力士乐

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R900931371 4WREE10W50-2X/G24K31/A1V
4WRE6W1-16-1X/24K4/M


这些阀组合了先导辅控式平衡阀和经C3端口进行制动的梭阀的功能;它们能用在两侧等截面、并带有超限负载和弹簧加载保持制动功能(典型的设备，是由液压马达驱动的绞盘)的执行器上。

　　在绞盘回路中，当负载下降时，由超限负载所引起的压力保持不变，可将先导比R选得尽可能高，以便加快速度并节省能量。但考虑到的是，打开平衡阀所需的“先导压力”，始终“”制动解锁压力(一般为15~20bar)。实际上，当负载开始下降时，建立的先导管路压力达到制动卸荷的压力设定值，才能打开平衡阀，并使马达开始转动。对于液压马达而言，打开平衡阀所需的先导压力值可由以下公式计算得到：
　　Ppil = ( Pt-Pload ) / ( R+1 )
　　低先导压力(Ppil)为： (Ppilmin)= ( Pt – Ploadmax ) / ( R+1 )
　　这里：
　　Pt = 压力设定值(溢流阀设定)
　　Pload = 负载所引起的压力
　　R = 先导比
　　举例：
　　Ploadmax =170bar ( f负载所引起压力的大预期值)
　　Pt = 325bar (> 1.3*170 bar )
　　R = 8:1 ( 先导比 )
　　制动卸荷压力 > = 17 bar
　　(Ppilmin) = (350-170) / (8+1) bar = 20bar > 17bar
　　由于低先导压力大于17bar，因此所选的平衡阀，相关参数为R=8:1 且Pt=350bar,符合正确的下降顺序要求。
　　如果不符合要求，就应当选择其它的先导比或压力值。

4WRE6W1-16-1X/24K4/M